KSK
Last Activity: 9 Years ago
H=12
M1=60KG, V1=?,M2=0.5KG, V2= 4 m/s
USING CONSERVATION OF MOMENTUM
INITIAL MOMENTUM= FINAL MOMENTUM
0 = M1*V1+M2*V2
M1*V1=(-M2*V2)
60*V1=(-0.5*4)
V1= (-1)/15 = 1/15 m/s (IN UPWARD DIRECTION)
(T) TIME TAKEN BY STONE TO REACH GROUND = DISTANCE/SPEED
T= 12/4 = 3 sec
(D) DISTANCE COVERED IN UPWARD DIRECTION BY MAN WHEN STONE HITS GROUND=
3 * (1/15)
D= 1/5= 0.2m
DISTANCE BETWEEN GROUND AND MAN = 12+0.2 = 12.2 m