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`        A hydrocarbon contains 10.5g of carbon per gram of hydrogen. 1 litre of the vapour of the hydrocarbon at 127oC and 1 atmosphere pressure weighs 2.8g. find the molecular formula.`
5 years ago

Jitender Pal
365 Points
```
Given P = 1 atmV = 1L, T = 127oC = 127 + 273 = 4000K

PV = nRT (Ideal gas equation)

Or n =PV/RT = 1 *1/0.082 *400 = 0.0304

Mol. wt Mass/Moles = 2.8/0.0304 = 92.10

Element

Wt. of element

Relation no. of atom

Ratio of of atoms

Whole no. of atoms

C

H

10.5

1.0

10.5/12

= 0.875

1.0/1 = 1

0.875/0.875

= 1

1/0.875 = 1.14

1 * 7 = 7

1.14 *7 = 8

∴ Emperical formula = C7H8­

Emperical formula, wt = 12 * 7 + 1 * 8 = 92

n = Molecular wt/Emperical formula wt = 92.10/92 = 1

molecular formula = n * empirical formula

= 1 (C7H8) = C7H8

```
5 years ago
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• 141 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
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