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A hydrocarbon contain 80% C.The vapour density of compound is 30.Empirical compound is
V.D.=m/230*2=m=60(wt of hydrocarbon)It contains 80% carbonI.e., 80*60/100=48g carbonAnd remaining hydrogen is 60-48=12g hydrogenNow for em.formulaFind out moles of C and H using W/M= no.of moles48/12:12/11:4CH4
V.D.=m/230*2=m=60(wt of hydrocarbon) It contains 80% carbonI.e., 80*60/100=48g carbon .And remaining hydrogen is 60-48=12g hydrogenNow for em.formula. Find out moles of C and H using W/M= no.of moles48/12:12/1 1:4 CH4
In CH4 the percentage of carbon is 75 and that of hydrogen is 25.I there is some mistake in the question.
Hello Student,I have attached image for the same.RegardsIHE
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