Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A good vacuum produced in common laboratory apparatus corresponds to 10^-6mm pressure at 25℃. Calculate no. Of molecules per cc at this pressure and temperature.(Ans:-3.2×10^10)
From PV =nRT1.3 x 10^-9 * 10^-3 = n * 0.0821 * 300n = 0.0527 x 10^-12 no. of molecules = n x Na => 0.0527 x 10^-12 x 6.023 x 10^23 = > 0.317 x 10^11 or => 3.17 x 10^10
How you got the volume? Plz explain the answer in descriptive manner.
1 ml divided by 1000 ml/ liter divided by 24.1 liters per mole multiplied by 6.023 molecules per mole divided by 760 mm Hg multiplied by 1 x 10^-6 mm Hg = molecule per ml at the reported temperature and pressure reported as one significant figure..
10^-6mm=10^-6/760atmvolume=1l=1000c.cPV=nRT10^-6/760atm*1000=n.*0821*298(25^0 c=298k)n=10^-6/760atm*1000 / 0821*298n=0.0538*10^-6 mole per c.cno .of moleclue per c.c=0.0538*10^-6 * 6.022 * 10^23 =3.2*10^16
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -