A golf ball has a mass of 40g, and a speed of 45 m/s. If the speed can be measured within accuracy of 2%, calculate the uncertainty in the position.
sudhanshu
12 Years agoGrade 12
3 Answers
Pankaj
11 Years ago
Given, The uncertainty in the speed is 2% Therefore, 45 x 2/100 = 0.9ms-1 . Now, dxdp = h/4 = (6.626 x 10-34 Js) / (4x3.14 x 40gx10-3 kg g-1 x 0.9m s-1) =1.46 x10-33 m Hence, the uncertainty in position is 1.46 x 10-33 m
irfan noushad
7 Years ago
Use Heisenberg's uncertainty principle, e.g., ∆x = h/4πm∆v Here, ∆x is the uncertainty in position ∆v is the uncertainty in velocity m is the mass of Particle .
Given, m = 40g = 0.04kg ∆v = 2% of v = 2 × 45/100 = 0.9 m/s h = 6.626 × 10⁻³⁴ J.s Now, ∆x = 6.626 × 10⁻³⁴/(4 × 3.14 × 0.04 × 0.9) = 14.654 × 10⁻³⁴ m
Hence, uncertainty in position = 1.4654 × 10⁻³³ m
Kushagra Madhukar
6 Years ago
Dear student,
As given in the question,
Δv = 2% of v = 2/100 x 45 = 0.9ms-1 .
Now, Δx.Δp = h/4 = (6.626 x 10-34 Js) / (4x3.14 x 40gx10-3 kg g-1 x 0.9m s-1) = 1.46 x10-33 m
Hence, the uncertainty in position is 1.46 x 10-33 m