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a given volume of methane gas diffuses in 40s. How long will it take the volume of sulphur (iv) oxide to diffuse under the same condition

nur , 7 Years ago
Grade 6
anser 1 Answers
Arun

Last Activity: 7 Years ago

The two gases are of equal volumes,
t1/t2 = √m1 /√m2
40/ t2 = √16/ √64
40/ t2 = 1 /√4
40/t2 = 1/2
hence
t2 = 80 sec.

Regards
Arun (askIITians forum expert)
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