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Grade 12Physical Chemistry

A FCC crystal of O^-2 (oxide) ions has M^+n ions in 50% of octahedral void then the value of n is1) 2 2) 3 3)4 4)1

Profile image of Mustufa Siddiqui
9 Years agoGrade 12
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1 Answer

Profile image of Ashish Kumar
9 Years ago
The answer is 3) 4.
In FCC crystal the number of octahedral voids = 4
50% of them are occupied by the metal ion so no of voids occupied =2, hence the number of metal ions =2
In FCC lattice the total number of O2- atoms are =4 ( 8 at corners and 6 at face centers)
Therefore the formula of the compound becomes M2O4 = MO2.
Now since the cahrge on a compond is zero so 1 x n +( 2 x -2) = 0
=> n=4 Answer

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