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Grade 11Physical Chemistry

A definite amount of gaseous hydrocarbon was burnt with just sufficient amount of O2. The volume of all reactants was 600 ml, after the explosion the volume of the products [CO2(g) and H2O (g)] was found to be 70p ml under the similar condition. The molecular formula of the compound is ???

Profile image of Neeraj Gupta
9 Years agoGrade 11
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1 Answer

Profile image of Vikas TU
9 Years ago
It is a standard hydrocarbon burning 
CxHy +(x+y/4)CO2= xCO2 +(y/2) H2O 
Discovering x and y utilizing pv=nrt. You get C3H8.