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Grade 11Physical Chemistry

A current of 5 amperes is passed for 1930 seconds through an aqueous solution of copper(II) sulphate. The mass, in grams, of copper deposited will be:

Profile image of lily
9 Years agoGrade 11
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1 Answer

Profile image of Vikas TU
9 Years ago
From Faraday’s first la,
W = Z*Q
5*1930*2 = W
W = 19300 gm
or
19.3 kgs.
Z =2 as the CuSO4 has the valence factor as 2.