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A cubical block of side a is moving with velocity v on a horizontal smooth plane as shown in the figure.it hits a ridge at point O.the angular speed of block after it hits O is
1)4v/3a
2)3v/4a
3)3v/2a
4)2v/3a

sheema , 8 Years ago
Grade 12th pass
anser 2 Answers
Vikas TU
From the angular momentum Conservation at about point O when it topples we get,
mva/2 = (ma^2/6 + m(a/root2)^2)w
on solving we get,
w = 3v/4a rad/s
Last Activity: 8 Years ago
Vishwacharan
According to the lawof conservation of angular momentum:
L1=L2
MV(a/2)=(2/3Ma^2)w.     (*=>here M.I of cube is
w=3V/4a.                                    2/3Mr^2)
Last Activity: 6 Years ago
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