Hello Student
Let the number of electrons present in ion A3+ be x
∴ Number of neutrons in it =x+ 30.4% ofx= 1.304x
Since the ion is tripositive,
⇒ Number of electrons in neutral atom =x+ 3
∴ Number of protons in neutral atom =x+ 3
Given,
Mass number of the ion = 56
(x+3)+(1.304x) = 56
2.304x = 53
x = 23
∴ Number of protons =x+ 3 = 23 + 3 = 26
∴ The symbol of the ion Fe3+