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a certain dye absorbs light of certain wavelength and then fluorescence light of wavelength 5,000 A° assuming that under given conditions 50% of the absorbed energy is reemitted out as Fluorescence and the ratio of number of quanta emitted out to the number of quanta absorbed is 5 ratio 8 find the wavelength of absorbed light

shauryaditya yadav , 6 Years ago

Grade 11

1 Answers

Eshan

Last Activity: 6 Years ago

Dear student,

Let the absorbed wavelength be $\lambda$ . Hence incident energy= $n_1\dfrac{hc}{\lambda}$
where $n_1$ is the number of quanta absorbed.

The emitted energy is $n_2\dfrac{hc}{\lambda'}$
It is given that $\dfrac{n_2}{n_1}=\dfrac{5}{8}$
Also the emitted energy is 50% of that absorved.
Hence $\dfrac{1}{2}\times n_1\dfrac{hc}{\lambda}=n_2\dfrac{hc}{\lambda'}$
$\implies \lambda=\dfrac{4}{5}\lambda'=4000A^{\circ}$

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