MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
A certain amount of a metal whose equivalent mass is 28 displaces 0.7L of H2 at STP from an acid hence mass of the element is (1) 1.75g  (2) 0.875g (3) 3.50g (4) 7.00g
one month ago

Answers : (1)

Vikas TU
8378 Points
							
1 mole of H2 at STP occupies volume = 22.4 L
No. of moles of  0.7 L H2at STP = 0.7/22.4 = 0.0313 moles.
Weight of Element (X) = Moles of H2 x eq wt of the metal  x mass of H2 
 X = 0.0313 x 28  x 2
X = 1.7528 grams 
one month ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details