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A certain amount of a metal whose equivalent mass is 28 displaces 0.7L of H2 at STP from an acid hence mass of the element is (1) 1.75g (2) 0.875g (3) 3.50g (4) 7.00g

A certain amount of a metal whose equivalent mass is 28 displaces 0.7L of H2 at STP from an acid hence mass of the element is (1) 1.75g  (2) 0.875g (3) 3.50g (4) 7.00g

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
1 mole of H2 at STP occupies volume = 22.4 L
No. of moles of  0.7 L H2at STP = 0.7/22.4 = 0.0313 moles.
Weight of Element (X) = Moles of H2 x eq wt of the metal  x mass of H2 
 X = 0.0313 x 28  x 2
X = 1.7528 grams 

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