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`        A buffer of ph 9.26 is made by dissolving x moles of ammonium sulphate and 0.1 mole of ammonia into 100ml solution . If pk(b) of ammonia is 4.74 , then calculate value of x.`
one year ago

Sahani Kumar
99 Points
```							pH=
```
one year ago
Sahani Kumar
99 Points
```							pH=pKb+log[salt]/[base]      given: pH=9.26, pKb = 4.74           [salt]=x mole/L           [base]=(0.1*1000)/100= 1mol/LNow 9.26=4.74+log[x]/[1]         4.52=log[x]          x=10^-4.52=3.02*10^-5^
```
one year ago
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