A box of 1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be- A) P B) 2P C) P/2 D) P4

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Arun · Answer

n(H2)=1 and n(CH4) = 1 P(H2) = (1/(1+1))*P =P/2 P(H2) = P/2 P(CH4) = 1/(1+1)P = P/2 so p(tot) = P Regards Arun (askIITians forum expert)

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A box of 1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be- A) P B) 2P C) P/2 D) P4

A box of 1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be-
A) P
B) 2P
C) P/2
D) P4

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A box of 1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be- A) P B) 2P C) P/2 D) P4

A box of 1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be-A) PB) 2PC) P/2D) P4

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A box of 1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H2 and 16g CH4 respectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be-
A) P
B) 2P
C) P/2
D) P4