Given %v/v =12%, means 12ml solute(ethanol) in 100ml solution.
Thus, mass of ethanol =v×d =12×0.8 =9.6gm
moles of ethanol=9.6/46 mol
Volume of solvent =(100-12)ml=88ml
Here, solvent H2O , so density of solvent =1g/ml
Mass of solvent =88×1=88gm
Mass of solution=mass of solute+mass of solvent
=9.6+88=97.6gm
Now, a) molality = moles of solute /mass of solvent in kg
=9.6/46 ÷88/1000 = 2.37m
b) Molarity =moles of solute/volume of solution in Litre
=9.6/46 ÷ 100/1000 = 2.08M
c) %w/w =(mass of solute/mass of solution) ×100
=(9.6 ÷ 97.6) ×100 = 9.83%
Thanks.
It was a brilliant question, where most important thing was to take volume conserved.