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Grade 11Physical Chemistry

a beaker of circular cross section radius 4cm is filled with hg upto height 10cm. the force exerted by the mercury on the bottom of the beaker will be

Profile image of Toshi Anand
8 Years agoGrade 11
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1 Answer

Profile image of Sachin
8 Years ago
P= F/AArea= πr2 = 3.14*4*4= 50.24cm2= 0.005024m2P=hdg= 0.1*13.6*10^3*9.8= 13.328kpaHere d is density of mercury.Now F= P*A= 13.328*0.005024 66.99= 67N