Dear Student,
According to Graham's law of effusiin we know that
Rate is proportional to 1/√d
So, here r = k/ (m/2)^1/2 = k. (2/m)^1/2
So, ration of composition during effusion is
r1:r2 =[(2/m1)/(2/m2)]^1/2
r1/r2= (1.16/4.4)^1/2
So. Composition of mixture leaking is equal in proportion.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)