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A 4:1 molar mixture of He and CH4 is contained in avessel at 20 atm pressure.Due to a hole in vessel, the gas mixture leaks out.What is the composition of the mixture effusing out initially?..........
Here,total moles = 4+1 =5,Total pressure = 20 barsSo, partial pressure of He = 4/5 x 20 = 16 bar Or,partial pressure of CH = 20-16 = 4 barNow, molar mass of He = 4, molar mass of CH = 16 So, ratio of rate of effusion of He (r ) and rate of effusion of methane (r ) will be=8(by calculating)Hence, as the rate of effusion of He is 8 times higher than CH so, initial mixture must contain the molar ratio of He: CH to be 8:1.
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