Question icon
Grade 12Physical Chemistry

A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second.

Profile image of sudhanshu
12 Years agoGrade 12
Answers icon

2 Answers

Profile image of Gaurav
11 Years ago
255-158_images.jpg
Profile image of Kushagra Madhukar
6 Years ago
Hello Student,
 
In the given question, the energy in a single photon =hv = hc/λ
                                                                                          = 6.626 x 10-34 x 3 x 108 / 0.57 x 10-6 
                                                                                          = 3.4874 x 10-19 J
Now, Quanta(photon) per second will be obtained as
  Energy emitted per second(or power) by bulb / energy of a single photon
= 25 Js-1 / 3.4874 x 10-19 J
= 7.17 x 1019 s-1
 
Hope it helps.
Regards,
Kushagra