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Grade: 12th pass 

                        
A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57um.calculate the rate of emission of quanta per second
2 years ago

Answers : (1)

Khimraj
3007 Points 
							
Power of bulb, P = 25 Watt = 25 Js–1
energy of photon 
E = hc/\lambda = 34.87*10-20 J
rate of emission of quanta per second = P/E = 7.2*1019 s-1
Hope it clears.
2 years ago
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