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Grade 12th passPhysical Chemistry

A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57um.calculate the rate of emission of quanta per second

Profile image of Ujwala Sharma
7 Years agoGrade 12th pass
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1 Answer

Profile image of Khimraj
7 Years ago
Power of bulb, P = 25 Watt = 25 Js–1
energy of photon 
E = hc/\lambda = 34.87*10-20 J
rate of emission of quanta per second = P/E = 7.2*1019 s-1
Hope it clears.