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A 150ml of solution of i2 is divided into two unequal parts. I part reacts with hypo solution in acidic medium. 15ml of 0.4M hypo was consumed. II part was added with 100ml of 0.3M NaoH solution residual base required 10ml of 0.3M H2SO4 solution for complete neutralization. What was initial concentration of I2
Na2S2O3+I2=Na2S4O6+NaIMilli moles of Na2S2O3 consumed=6millimoles of I2 reacted with naoh=12total millimoles of I2 consumed in the reaction=15initial concentration=15/150=0.1M
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