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Grade 7Physical Chemistry

A 10cm of column of air is trapped by a column of mercury 8cm long in a capillary cube horizontally fixed below that one atm pressure then calculate the length of air column when the cube is fixed at the same temperature. A) vertically opened end up.B) vertically opened end down.C) at 45 degree with a horizontal opened end up.

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10 Years agoGrade 7
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ApprovedApproved Tutor Answer1 Year ago

To solve this problem, we need to apply the principles of gas laws, particularly Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature is held constant. In this scenario, we have a column of air trapped by a column of mercury, and we want to determine how the length of the air column changes based on different orientations of the capillary cube.

Initial Conditions

We start with a 10 cm column of air and an 8 cm column of mercury. The pressure exerted by the mercury column can be calculated using the density of mercury and the gravitational force. At one atmosphere (atm) pressure, the mercury column exerts a pressure of approximately 760 mmHg, which is equivalent to 76 cm of mercury. Therefore, the total pressure on the air column is the atmospheric pressure minus the pressure exerted by the mercury column.

Calculating the Initial Pressure

The pressure exerted by the 8 cm mercury column is:

  • Pressure of mercury (P_mercury) = height of mercury column × density of mercury × g
  • For simplicity, we can use the height directly since we are working with relative pressures.

Thus, the pressure on the air column is:

  • P_air = P_atm - P_mercury = 1 atm - (8 cm of mercury / 76 cm of mercury) × 1 atm

Case A: Vertically Opened End Up

When the capillary cube is oriented with the open end facing upwards, the air column will expand due to the reduction in pressure from the mercury column. The new length of the air column can be calculated using Boyle's Law:

  • P1 × V1 = P2 × V2

Here, V1 is the initial volume of the air column (10 cm), and P1 is the initial pressure. P2 is the new pressure, which is now equal to atmospheric pressure (1 atm), and V2 is the new volume we want to find. Rearranging gives us:

  • V2 = (P1 × V1) / P2

Substituting the values will yield the new length of the air column.

Case B: Vertically Opened End Down

In this orientation, the air column is compressed by the atmospheric pressure acting on the mercury. The pressure on the air column will be greater than in the previous case. Again, we apply Boyle's Law:

  • P1 × V1 = P2 × V2

In this case, P2 is the sum of atmospheric pressure and the pressure from the mercury column. The new volume can be calculated similarly, leading to a shorter air column compared to the first case.

Case C: At 45 Degrees with Open End Up

When the cube is at a 45-degree angle, the situation becomes a bit more complex due to the geometry involved. The effective height of the air column will be influenced by both the vertical and horizontal components of the pressure. However, we can still use Boyle's Law, but we need to account for the change in volume due to the angle:

  • V = length × cross-sectional area

We can calculate the effective height of the air column and apply Boyle's Law as before, but we must consider the angle when determining the new volume. The length of the air column will be somewhere between the lengths calculated in the first two cases.

Summary of Results

In summary, the length of the air column will vary based on the orientation of the capillary cube:

  • Open end up: The air column expands, resulting in a longer length.
  • Open end down: The air column compresses, resulting in a shorter length.
  • At 45 degrees: The length will be intermediate, depending on the effective pressure and volume calculations.

By applying these principles, you can derive the exact lengths for each case based on the initial conditions provided. If you need further clarification on any specific calculations, feel free to ask!