Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
`        A 1.2% solution of NaCl is isotonic with 7.2% solution of glucose. Calculate the value of Vant Hoff factor of NaCl.`
one year ago

## Answers : (1)

Arun
23044 Points
```
we have, as percentage of weight/volume = (wt. of solute/volume of solution)× 100
Therefore, wt. of glucose = 7.2 g ; volume of solution = 100 mL
For glucose : πexp or πN = {w/(m × V)} × ST [V in litre]
As, πexp or πN = (7.2 × 1000 × 0.0821 × T)/(180 × 100)
For NaCl      πN = {w/(m × V)} × ST
= (1.2 × 1000 × 0.0821 × T)/(58.5 × 100)
As, two solutions are isotonic and hence,
πexpNaCl = πNglucose
Therefore, for NaCl : πexp/πN = 1 + α
Or, {(7.2 × 1000 × 0.082 × T)/(180 × 100)} × {(58.5 × 100)/(1.2 × 1000 × 0.082 × T)} = 1 + α
= i T
herefore, α = 0.95 & i = 1.95
Regards
Arun (askIITians forum expert)

```
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details