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Grade: 12th pass
        
a 0.02M solution of latic acid has ph =2.8 calculate the approximate ka for lactic acid
one year ago

Answers : (1)

Sahani Kumar
99 Points
							
Given: c= 0.02   pH=2.8
 Now, pH= -log[H+]            [H+]= concentration of H+
           2.8= - log[H+]
           [H+]=1.58*10^-3
We know that α =[H+] = 1.58*10^-3
     Now, Ka=c α^2
               Ka= 0.02 * (1.58*10^-3)^2
               Ka=5*10^-8
Regards 
Askiitian member
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one year ago
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