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6g of the organic compound on heating witg. NaOH gaue NH3 which is neutralised by 200ml of 1NHCl. percentage of nitrogen is?

saket kumar , 12 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To determine the percentage of nitrogen in the organic compound, we need to analyze the reaction that occurs when the compound is heated with sodium hydroxide (NaOH) and how it interacts with hydrochloric acid (HCl). Let's break this down step by step.

Understanding the Reaction

When the organic compound is heated with NaOH, it likely undergoes a process called hydrolysis, which can release ammonia (NH3). The ammonia produced can then react with hydrochloric acid (HCl) to form ammonium chloride (NH4Cl).

Calculating Moles of HCl

We know that 200 mL of 1 N HCl is used to neutralize the ammonia. First, we need to calculate the number of moles of HCl:

  • Normality (N) of HCl = 1 N
  • Volume of HCl = 200 mL = 0.2 L
  • Moles of HCl = Normality × Volume = 1 N × 0.2 L = 0.2 moles

Relating Moles of NH3 to Moles of HCl

In the neutralization reaction, one mole of NH3 reacts with one mole of HCl. Therefore, the moles of NH3 produced will also be 0.2 moles.

Finding the Mass of Nitrogen

Next, we need to find the mass of nitrogen in the ammonia. The molecular formula for ammonia is NH3, which contains one nitrogen atom per molecule. The molar mass of nitrogen (N) is approximately 14 g/mol.

  • Moles of NH3 = 0.2 moles
  • Mass of nitrogen = Moles of NH3 × Molar mass of N = 0.2 moles × 14 g/mol = 2.8 g

Calculating the Percentage of Nitrogen

Now that we have the mass of nitrogen, we can calculate the percentage of nitrogen in the original organic compound. The total mass of the organic compound is given as 6 g.

  • Mass of nitrogen = 2.8 g
  • Percentage of nitrogen = (Mass of nitrogen / Total mass of compound) × 100
  • Percentage of nitrogen = (2.8 g / 6 g) × 100 ≈ 46.67%

Final Thoughts

Thus, the percentage of nitrogen in the organic compound is approximately 46.67%. This calculation illustrates how we can derive the nitrogen content from the reactions involved and the stoichiometry of the compounds. If you have any further questions or need clarification on any part of this process, feel free to ask!

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