64th quen plš......................................................
64th quen plš......................................................
Mehul Verma , 7 Years ago
Grade 12
Physical Chemistry> 64th quen plš...............................
1 Answers
Arun
We have 20 ml of 0.95 M of K
2
Cr
2
O
7
7
On dilution to 200 ml
M
1
V
1
=M
2
V
2
0.95×20=200×M
2
M
2
=0.095 M
We have 0.095 M, 25 ml K
2
Cr
2
O
7
added with 50 ml, 4 M H
2
SO
4
, then concentration of K
2
Cr
2
O
7
will be
M
2
V
2
=M
3
V
3
0.095×25=(25+50)×M
3
M
3
=0.03167 M K
2
Cr
2
O
7
30 ml of 0.03167 M K
2
Cr
2
O
7
is diluted to 150 ml
M
3
V
3
=M
4
V
4
0.03167×30=150×M
4
M
4
=0.00633 M K
2
Cr
2
O
7
_________________________
We have final conc. of K
2
Cr
2
O
7
=0.00693M
We have reaction,
K
2
Cr07+4H
2
SO
4
+3H
2
O
2
→Cr
2
(SO
4
)
3
+K
2
SO
4
+2H
2
O+30
2
milli moles of K
2
Cr
2
07= millimoles of H
2
O
2
× stoichimetric ratio
0.00633×15=V×0.02×
3
1
V=14.25ml
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