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Grade: 11
        
600 ml of  a mixture of O3  and 
O2  weighs 1g at NTP. Calculate 
the volume of ozone in the mixture. Please give solution.
3 years ago

Answers : (1)

Sumit Majumdar
IIT Delhi
askIITians Faculty
137 Points
							
Solution:
Let us assume x g of oxygen and y g of ozone.
Hence the moles for oxygen and ozone would be equal to:
\frac{x}{32}; \frac{y}{48}
Now the volume occupied by oxygen and ozone would be equal to:
\frac{x}{32}\times 22.4; \frac{y}{48}\times 22.4
Therefore,
we get:x=0.57 and y=0.428
So the volume of ozone would be equal to:0.2 litres.
Thanks & Regards
Sumit Majumdar,
askIITians Faculty
Ph.D,IIT Delhi
3 years ago
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