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        600 ml of  a mixture of O3  and O2  weighs 1g at NTP. Calculate the volume of ozone in the mixture. Please give solution.
3 years ago

Sumit Majumdar
IIT Delhi
137 Points
							Solution:Let us assume x g of oxygen and y g of ozone.Hence the moles for oxygen and ozone would be equal to:$\frac{x}{32}; \frac{y}{48}$Now the volume occupied by oxygen and ozone would be equal to:$\frac{x}{32}\times 22.4; \frac{y}{48}\times 22.4$Therefore,we get:x=0.57 and y=0.428So the volume of ozone would be equal to:0.2 litres.
Thanks & Regards

Sumit Majumdar,

Ph.D,IIT Delhi


3 years ago
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