Vikas TU
Last Activity: 8 Years ago
let the metal carbonate be:
M2(CO3)X
molar mass = 2M + 60x
moles = 6.9/( 2M + 60x)
Now,
Molarity = Normality/V.F
= 2/1 = 2
MV = moles
moles = (2*60-20*1)/1000 = 100/1000 = 0.1 { 20 mm neutralized by OH-}
6.9/Z = 0.1
Z = 6.9/0.1
Z = 69
Molar mass of metal carbonate is hence, 69.
moles of metal = 0.1*2 = 0.2
Eq. Weight = moles x valence factor.
= 0.2 x 2
= 0.4