Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
500 ml of gaseous hydrocarbon when burnt in excess of of O2 gave 2.5 l of CO2 and 3.0 l of H20(vap) the hydrocarbon is
Write the eqn. first and balance it. CxHy + (2x + y/2)O2 =======> xCO2 + (y/2)H2O moles = 0.5/22.4 moles = 2.5/22.4 moles = 3/22.4 Now,from limiting reagent concept, 0.0223/1 = 0.111/xorx = 4.9 approx. 5thus, x = 5and also0.0233/1 = 0.1339*2/y0.0233 = 0.2678/yory = 11.5 that is approx. we woukd take 12.therfore y =12the hydrocarbon is:C5H12.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -