50 ml of 2M naoh solution is reacted with 50 ml of 2M H2so4b,find the molarity of H2S o4 in resulting solutionH2so4+ 2naoh ~ na2so4 +2h20*. ~ means gives

To determine the molarity of sulfuric acid (H2SO4) in the resulting solution after the reaction with sodium hydroxide (NaOH), we first need to analyze the chemical reaction and the amounts of each reactant involved.

The Reaction Overview

The balanced chemical equation for the reaction between sulfuric acid and sodium hydroxide is:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

This indicates that one mole of sulfuric acid reacts with two moles of sodium hydroxide to produce one mole of sodium sulfate and two moles of water.

Calculating Moles of Reactants

Next, we need to calculate the number of moles of each reactant used in the reaction. The formula to find the number of moles is:

Number of moles = Molarity × Volume (in liters)

• For NaOH:
  • Molarity = 2 M
  • Volume = 50 ml = 0.050 L
  • Number of moles of NaOH = 2 M × 0.050 L = 0.1 moles
• For H2SO4:
  • Molarity = 2 M
  • Volume = 50 ml = 0.050 L
  • Number of moles of H2SO4 = 2 M × 0.050 L = 0.1 moles

Determining the Limiting Reactant

From the balanced equation, we see that one mole of H2SO4 reacts with two moles of NaOH. Since we have 0.1 moles of H2SO4, it would require:

0.1 moles H2SO4 × 2 = 0.2 moles NaOH

However, we only have 0.1 moles of NaOH available. This means NaOH is the limiting reactant, and H2SO4 will be in excess.

Calculating Remaining Moles of H2SO4

Since NaOH is the limiting reactant, we can determine how much H2SO4 reacts with the available NaOH:

0.1 moles NaOH will react with 0.1 moles NaOH / 2 = 0.05 moles H2SO4

Now, we can find out how much H2SO4 remains after the reaction:

Initial moles of H2SO4 - Moles of H2SO4 reacted = 0.1 moles - 0.05 moles = 0.05 moles

Finding the Molarity of H2SO4 in the Resulting Solution

After the reaction, the total volume of the solution is the sum of the volumes of the reactants:

Total volume = 50 ml + 50 ml = 100 ml = 0.1 L

Now, we can calculate the molarity of the remaining H2SO4 in the resulting solution:

Molarity = Number of moles / Volume (in liters)

Molarity of H2SO4 = 0.05 moles / 0.1 L = 0.5 M

Final Result

The molarity of H2SO4 in the resulting solution after the reaction with NaOH is 0.5 M.