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Grade 11Physical Chemistry

50 g of CaCO3 is allowed to react with 70 g of H3PO4. Calculate :
  1. Amount of Ca3(PO4)2 formed
  2. Amount of unreacted reagent

Profile image of Sidharth
8 Years agoGrade 11
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer8 Years ago
 
CaCo3 + H3Po4 ~ ca3(po4)2 + h2o + co2
 According to the above reaction 100 gm of caco3 reacts with 98 gm H3po4 which implies
50 gm of CaCo3 will react with 48 gm of h3po4 .....
 
100 gm of Caco3 gives 310 gm of ca3(po4)2 which implies 50g caco3 will give 155gm ca3(po4)2
 
Therefore, 155g ca3(po4)2