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Grade: 11

                        

50 cc of 0.2 N of HCl is titrated against 0.1 N NaOH solution. The titration is discontinued after adding 50 cc of NaOH. The remaining titration is completed by adding 0.5M KOH. the volume of KOH required for completing the titration is.... ( this question has already been answered but plz show me the steps as am not understanding how to proceed with the problem)

2 years ago

Answers : (1)

Avni Chauhan
askIITians Faculty
247 Points
							the no. of H+coming out of a solution = The no. of OH-coming out
hence N1V1 = N2V2 + N3V3
where, 1 is HCl
2 is NaOH and 3 is KOH

50 x 0.2 = 50 x 0.1 + 0.5 x ?
Thats it, find out volume of KOH
2 years ago
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