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Grade 11Physical Chemistry

5 moles of Na₂S₂O₃ loses 40 moles of electron . Determine new oxidation no. of sulphur

Aryan Tripathi

7 Years agoGrade 11

1 Answer

Pooja

7 Years ago

Here the combined oxidation no of both S atoms would be

2(Na)+2(S)+3(O)=0

2(1)+2(S)+3(-2)=0

2(S)=+4

1 mole has +4

5 mole will have ON= +20

5S₂O₃^-2 = 10SO₄^-2 + 40e^-

+20 -40

It is clear from the above rection that the ON of 10 mole product will be 20 - (-40) = +60

So ON of one mole will be +6

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