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5.3g of M2CO3 is dissolved in 150ml of 1N HCL. Unused acid requires 100ml of 0.5 N NaOH. Hence equivalent weight of M is?

bani , 10 Years ago
Grade 12th pass
anser 2 Answers
Sakshi

Last Activity: 9 Years ago

hey student..
the trick behind this question is to start from the last reaction and keep on moving in the backward reaction also keep in mind the concept of number of equivalents..the no of equi\valent of acids so used is the same as that of salt used up
Vedant Vairagi

Last Activity: 8 Years ago

Start from the end for naoh Equate mini equivalents100×1×0.5=v×1×1V=50Thus 50 ml is used and 100 ml takes part in reactionThus by equivalence100×1×1=5.3/eq wt × 1000Eq wt = 53Thus equivalent weight of M is 53
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