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4/3Al+o2->2/3Al2o3 here the value of (n ) no. of electrons exchange is

4/3Al+o2->2/3Al2o3 here the value of (n ) no. of electrons exchange is

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago

The balanced equation becomes by multiplying both side with 3,

4 Al + 3O2 -> 2Al2O3

So, the reaction produces, Al -> Al+3 + 3e- 

Hence, the no. of electrons exchanged, n = 3

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