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3Cu+pHNO 3 3Cu(NO 3 ) 2 +4H 2 O+xNO. IIIIIIIIIII In the equation above, the values of p and x respectively are ?

3Cu+pHNO3Cu(NO3)2+4H2O+xNO. IIIIIIIIIII
In the equation above, the values of p and x respectively are ?

Grade:10

1 Answers

vibhuti agrawal
26 Points
5 years ago
Equation can be Balanced by oxidation number method
Oxidation number of Cu in LHS is zero and that on RHS is +2
Same way oxidation number of N is changing from +5 in HNO3 to +2 in NO
 
Value of P is 8 
And that of x is 2

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