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3Cu+pHNO 3 3Cu(NO 3 ) 2 +4H 2 O+xNO. IIIIIIIIIII In the equation above, the values of p and x respectively are ?
Equation can be Balanced by oxidation number methodOxidation number of Cu in LHS is zero and that on RHS is +2Same way oxidation number of N is changing from +5 in HNO3 to +2 in NO Value of P is 8 And that of x is 2
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