Navjyot Kalra
Last Activity: 10 Years ago
Given, moles = mass/mol.wt
Mass of gas = 3.7 g, mass of hydrogen = 0.184g
T1 = 298K, T2 = 17oC = 273 + 17 = 290K
Moles of H2 = n1 = Mass/M. wt. = 0.184/2 = 0.092
Moles of gas = n2 = Mass/M. wt. = 3.7/M
For hydrogen P1V1 = n1RT1 …………..(i)
For gas P2V2 = n2RT2 …………….(ii)
(∵ Pressure and volume of gas |are same)
∴ From equation (i) and equation (ii)
P1V1/P1V1 = n1RT1/n2RT2 or 1 = 0.092 *298/n2 *290
or n2 = 0.092 *298/290 or 3.7/M = 0.092 *298/290
or 3.7/M = 0.0945
∴ M = 3.7/0.0945 = 39.15
