HELLO SHUBH,
do not worry i will help with your problem
its little tricky but simple in solving
i will explain you as follows please look out
since moles of AgCl = 7.74/143.5
moles of Cl- will aslo be 7.74/143.5
NOW,
let no of moles of KCl salt be = a moles
let no of moles of NaCl salt be = b moles
so,
a+b = 7.74/143.5
= 0.05 M
next,
3.6 = 74.5a + 58.5b
so after solving the above equation,
a=0.028
b = 0.026
next,
mass of KCl = 78.5 X a
= 78.5 x 0.028
=2.06gms
mass of NaCl = 58.5 X b
= 58.5 x 0.026
= 1.53gms\
therefore,
percentage of NaCl = 1.53/3.6 X 100
=42.5%
percentage of KCl = 2.06/3.6 X 100
= 57.4%
approve me if my solution is right
THANK YOU
