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Grade: 12
        
2CH3CHO+O2 forms 2CH3COOH.
If there is 20gm of acetaldehyde and 10gm of O2.Then which is limiting reagent?
AND BY WHAT EXTENT?
 
one year ago

Answers : (1)

Ambarish Kumar Banerjee
53 Points
							approach is :     we have to find which reagent restricts the use up of 100% reagents i.e. the reagent that gives less amount of products on complete use up. 20 gram i.e. 5/11 moles of acetaldehyde and 5/16 moles of o2 is present. from ch3cho 5/11 moles of acetic acid is obtained. from 5/16 moles of o2 5/8 moles of acetic acid is obtained. so we see less amount of acetic acid is obtained from acetaldehyde . there fore this is the limiting reagent. and the other(o2) is in excess . now by how much?5/11 moles of ch3cho reacts with 5/22 moles of o2(2:1 ratio from balnced equation). remaining  o2 is 5/16-5/22=15/176 moles or 2.73 gram.please approve if u feel it is properly explained
						
one year ago
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