0

Guest

Courses New

2CH 3 CHO+O 2 forms 2CH 3 COOH. If there is 20gm of acetaldehyde and 10gm of O 2 .Then which is limiting reagent? AND BY WHAT EXTENT?

2CH3CHO+O2 forms 2CH3COOH.
If there is 20gm of acetaldehyde and 10gm of O2.Then which is limiting reagent?
AND BY WHAT EXTENT?
 

Grade:12

1 Answers

Ambarish Kumar Banerjee
53 Points
7 years ago
approach is : we have to find which reagent restricts the use up of 100% reagents i.e. the reagent that gives less amount of products on complete use up. 20 gram i.e. 5/11 moles of acetaldehyde and 5/16 moles of o2 is present. from ch3cho 5/11 moles of acetic acid is obtained. from 5/16 moles of o2 5/8 moles of acetic acid is obtained. so we see less amount of acetic acid is obtained from acetaldehyde . there fore this is the limiting reagent. and the other(o2) is in excess . now by how much?5/11 moles of ch3cho reacts with 5/22 moles of o2(2:1 ratio from balnced equation). remaining o2 is 5/16-5/22=15/176 moles or 2.73 gram.please approve if u feel it is properly explained

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More