Grade 11Physical Chemistry
250ML OF 0.5M KCL IS DILUTED WITH WATER TO 500ML OF SOLUTION THE NO OF CHLORIDE IONS IN RESULTING SOLUTION IS?
250ML OF 0.5M KCL IS DILUTED WITH WATER TO 500ML OF SOLUTION THE NO OF CHLORIDE IONS IN RESULTING SOLUTION IS?
1 Answer
Kirtan Solanki
HERE,
MV=M’V’
(0.5)(250)=M’(500)
M’=0.25M
Now, 0.25M means that every 1000ml solution contains 0.25 moles of KCl...
thus,every 500ml solutionwould contain x moles of KCl
by cross multiplication....x=0.125 moles of KCl
moles of chloride ions=0.125moles
thus,no of cholide ions =0.125*(6.022*10^23)
=7.5*10^22 ions
hope this helps....
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