250m of 0.5M KCL is diluted with water in 500ml solution. What will be the number of chloride ions in the resulting solution
priyansh
9 Years agoGrade 12
1 Answer
Vikas TU
9 Years ago
Dear Student, Here in 1 lit it is 0.5 M. In 250/ml It is 0.5/4=0.125 M So, in case of resting solution the no of chloride ions are 0.125N/750 [N is avigadro np].