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`        25 g of a sample contains 50% MgCl2 and 50% MgSO4.The % of Mg in the mixture is.`
26 days ago

Rahul
39 Points
```							Given weight of mixture = 25gMolecular weight of mixture = 120 +95 =215gAmount of magnesium in mixture = 24/215 * 25 = 2.8g% of Mg in mixture = 2.8/25 * 100 = 11.16
```
25 days ago
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