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25 g of a sample contains 50% MgCl2 and 50% MgSO4.The % of Mg in the mixture is.
2 months ago

Answers : (1)

Rahul
39 Points
							
Given weight of mixture = 25g
Molecular weight of mixture = 120 +95 =215g
Amount of magnesium in mixture = 24/215 * 25 = 2.8g
% of Mg in mixture = 2.8/25 * 100 = 11.16
 
2 months ago
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