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25 g of a sample contains 50% MgCl2 and 50% MgSO4.The % of Mg in the mixture is.

one year ago

Answers : (2)

Rahul
39 Points
							
Given weight of mixture = 25g
Molecular weight of mixture = 120 +95 =215g
Amount of magnesium in mixture = 24/215 * 25 = 2.8g
% of Mg in mixture = 2.8/25 * 100 = 11.16
 
one year ago
Harshit
15 Points
							
Mwt of Mg*2/Mwt of mixture}*25=Weigt of Mg in mixture
%of Mg in mixture={weight of mg in mixture/given weight of mix}*100=22.63%
 
3 months ago
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