Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Titration of Na2CO3 using phenolphthalein as indicator involves the reaction: Na2CO3 + HCl = NaHCO3 + NaCl
so 1 Mole Na2CO3 consumes 1 Mole HCl
or 20 ml 0.1M Na2CO3 soln consumes 40 ml 0.05 M HCl soln. so x = 40.
Titration of Na2CO3 using methyl orange as indicator involves the reactions: Na2CO3 + 2HCl = H2CO3 + 2NaCl
and also NaHCO3 + HCl = H2CO3 + NaCl
so 1 Mole Na2CO3 consumes 2 Moles of HCl
and 1 Mole NaHCO3 consumes 1 Mole of HCl
or 20 ml 0.1M Na2CO3 soln consumes 40x2 ml 0.05 M HCl soln. and 20 ml 0.1M NaHCO3 soln consumes 40 ml 0.05 M HCl soln. (as the compound contains both Na2CO3 and NaHCO3 in equimolar proportion)
Hence y = 40x2+40 = 120
so y - x = 120 - 40 = 80.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !