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20g of impure calcium carbonate reacts with HCl and forms 6.6g of carbon dioxide. Calculate the purity of calcium carbonate.

20g of impure calcium carbonate reacts with HCl and forms 6.6g of carbon dioxide. Calculate the purity of calcium carbonate.

Grade:10

2 Answers

KOUstubh
11 Points
5 years ago
75 %
sd
write the equation
then balance it
calulate the mass of CO2that should be actually produced 
and then divid e the given amount of co2 by actual amount multiplied by 100
Abhiraj Pathak
82 Points
5 years ago
CaCO3 + 2HCl → CO2 + H2O + CaCl2
1 mole of CaCO3 gives 1 mole CO2
i.e 100g of CaCO3 produces 44g of CO2
Thus 6.6g is produced by (100 x 6.6)/44 = 15g of CaCO3.
Therefore, % purity of CaCO3 = 15/20 = 0.75 = 75%

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