Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        20 g of ammonium nitrate (NH4NO3) is dissolved in 125 g of water in a coffee-cup calorimeter, the temperature of which falls from 296.5 K to 286.4 K. Find the  value of q for the calorimeter (Treat heat capacity of water as the heat capacity of the calorimeter and its contents). (Ans= -5.285 kJ) Please explain why in the answer mass is taken to be only 125 g but not 125+20 g`
one year ago

Abhinav priye
15 Points
```							Mass of water =125 g(given)Change in temp =286.4-296.5=-10.1Specific heat of water in liquid form is 4.18Heat capacity=specific heat capacity*given mass=4.18*125=522.5Value of q=522.5*-10.1=5277.8=5.28kjValue of q=522.5*-10=
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions