0

Guest

Courses New

2 mole equimolar mixture of Na2C2O4 and H2C2O4 required V1 litre of 0.1 M KMnO4 in acidic medium for complete oxidation . The same amount of mixture required V2 litre of 0.2 M NaOH for neuterlization. The ratio of V1:V2 is

2 mole equimolar mixture of Na2C2O4 and H2C2O4 required V1 litre of 0.1 M KMnO4 in acidic medium for complete oxidation . The same amount of mixture required V2 litre of 0.2 M NaOH for neuterlization. The ratio of V1:V2 is

Grade:11

3 Answers

Vikas TU
14149 Points
7 years ago
From the equivalants concept,
moles x n-factor = constant.
Therfore,
(1*2) + (1*2) = 0.1*V1*5
we get,
V1 = 8
For V2,
2 + 2 = 0.2*V2*1
V2 = 4/0.2 => 20
Ratio V1/V2 = 8/20 => 2/5
or
2:5
PSK
13 Points
4 years ago
Answer will not be 2:5 as NaOH won't react with Na2C2O4 as it is a salt but will only react with H2C2O4.
Ravinder Gahlawat
26 Points
2 years ago
Answer will be 4:5 as NaOH only reacts with H2C2O4
 
Therefore, 1*2 = 0.2 * v2 * 1
 
             V2 = 10 
 
 
 
 
 
Jxjxjjcjcjjxjxjnsnxjjcjxjjsjsjcnjcjjxjsjjsmdnjcjcjxjjsjsmxncjcjc

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More