0

Guest

Courses New

2 g of impure CaCO3 reacts with HCI to produce 410 mL of CO2 at 1 atmospheric pressure and 27°C. Calculate the percentage purity of the CaCO3 used.

2 g of impure CaCO3 reacts with HCI to produce 410 mL of CO2 at 1 atmospheric pressure and 27°C. Calculate the percentage purity of the CaCO3 used.

Grade:12th pass

1 Answers

Atmik Goswami
13 Points
3 years ago
Firstly we convert volume of CO2 at STP.
1×410/300 = 1×V/273
or, V = 373.1 mL
We know at STP
22400 ml of CO2 weighs 44 g
So, 373.1 mL of CO2 weighs (44×373.1)/22400
or weight of CO2 is 0.732875 g.
Now we apply POAC on 'C':
1×x/100= 1×0.732875/44
or x=1.665625 g
So, percentage purity of CaCO3 is = 1.665625/2 ×100=83.28 %
or x=1.665625 g
So percentage of 

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More