Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        2.48 g of Na2S2O3.xH2O was dissolved per litre of the solution. 20 mL of this solution required 10 mL of 0.01 M iodine solution. Find out the value of x.`
2 years ago

```							Dear Student , We will use the formula :  Molarity (M) = no. of moles of solute / volume of solution in Litres Na2S2O3.xH2O was dissolved in 1L of some solution. Now, 20 mL of this solution required 10mL of 0.01M iodine solution.                               no. of moles = M * V  ( from the above formula )                               n ( iodine solution)= 0.01 * 10*10-3 = 10-4 moles                                 therefore , n ( solution) = 10-4  = Molarity of solution * volume of solution                                                                 10-4 = Msol * 20 * 10-3                                                 Msol = 0.005 Now, 2.48 g of Na2S2O3.xH2O  is dissolved in 1L this solution .  So, it is behaving as solute . Again using the same formula we will find the value of x :                                                  0.005 =  moles of solute / 1 L                                                  0.005 = given mass / molar mass                                                                                                  0.005 = 2.48 / {46+64+48+x (18)}                                        Now, solve this equation to get the value of x = ?                          Chemistry Consultant Askiitians
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions