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1mole of KClO3 is thermally decomposed and excess of aluminium is burnt in the gaseous product.How many moles of Al2O3 are formed?

1mole of KClO3 is thermally decomposed and excess of aluminium is burnt in the gaseous product.How many moles of Al2O3 are formed?

Grade:11

2 Answers

Arun
25750 Points
6 years ago

The thermal decomposition of KClO3 and the subsequent oxidation of Aluminum to form Al2O3.

Two reactions are: 

2 KClO3 → 2 KCl + 3 O2 and 4 Al + 3 O2 → 2 Al2O3 

The molar ratio for the first reaction is 2:3 for KClO3: O2. Thus, if 1 mole KClO3 is decomposed, 1.5 moles of O2 is produced ===> 1 mol KClO3 x ( 3 mol O2 / 2 mol KClO3) = 1.5 mol O2 


The molar ratio for the second reaction is: 3:2 for O2 : Al2O3. ===> 3 moles of oxygen produces 2 moles of aluminum oxide.

Since we have 1.5 moles of oxygen (half of the three needed) we can expect to produce half of the 2 moles or 1 mole aluminum oxide. Hence, 
1.5 mol O2 x ( 2 mol Al2O3 / 3 mol O2) = 1 mol Al2O3

Renu
13 Points
4 years ago
A.T.Q:- 
2KClO3------->2KCl +3O2   and   4Al +3O2 -------->2Al2O3               From the balanced equation  ;
2 moles of KClO3 produce 2moles Of Al2O3         ;         then
1 mole of KClO3 will produce 1moles of Al2O3.

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